Bob, I can reproduce Lee's problem, and it isn't because one square root is
inside the other (that is, it isn't inside). The difference in size appears to
be caused by the fact that (b/a) contains a letter with an ascender in the
numerator of the fraction, while (a/b) doesn't. If you change the expression to
"a\sqrt(b/a)+b\sqrt(d/b)" then both radicals become the same size.
--
Regards,
Jay Freedman
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http://word.mvps.org
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On Mon, 3 Mar 2008 21:34:23 -0800, "Bob Buckland ?:-\)" 75214.226(At
Beautiful Downtown)compuserve.com wrote:
Hi Lee,
The way it appears that you've constructed the equation you're computing one square root within the original one so that the first
square root 'symbol' is larger to attempt to show it's encompassing the full equation.
In fact the first sqrt symbol changes sizing from the time you first type it and then as you proceed through the equation.
The effect only appears if you have chosen 'Professional' display rather than 'Linear' for the equation. If in the Equation Tools
ribbon you click on the launcher (square box) on the bottom of the 'Tools' group and then choose the option
'Reduce size of nested fractions in display equations'
does that give you more of what you were expecting?
============
Lee wrote in message ...
When I typed "a\sqrt(b/a)+b\sqrt(a/b) if ab=9"
the height of the first radical became bigger than the second one.
This is a typical example. I am having a quite a few similar problems in
fractions.
Any thoughts???
Thanks in advance.