On Tue, 3 Jan 2006 08:47:47 +0200, "Graham Mayor"
wrote:
Or the revised version of it at
http://www.gmayor.com/replace_using_wildcards.htm
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Graham Mayor - Word MVP
OK. I have read both articles. Based on that, it seems to me that the
expression "[A-Za-z0-9[\]]" ought to find all of the letters and
numbers plus the square brackets ([]) in a Like comparison.
But it doesn't match any characters at all.
However, if I delete the "\]", leaving "[A-Za-z0-9[]", then it will
match all of the letters and numbers plus "[".
What am I doing wrong?
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Running Word 2000 SP-3 on Windows 2000