In Word2000 per the article;
http://support.microsoft.com/?kbid=212311
you can replace spaces with a tab specifying the minimum number of times the
space character must occur if I'm understanding this correctly:


To convert multiple instances of white space characters, such as spaces or
tab characters, to a single instance of the character, use the following
advanced criteria in the Find What box in the Find and Replace dialog box.
x{y,}

where x is the character you are searching for, such as a space, and y is
the minimum number of instances that the character must appear in order to be
replaced.

Can you do this in Word 2003? and if so how?
Thanks, Steve

Hmm...


http://support.microsoft.com/?kbid=212311


leads me to a page in German,

in case you are using a German, Dutch,
Norwegian?, Danish?, Swedish? ...? version,

the listseperator would be a semicolon ";",

US and most countries: x{y,}

some banana republics: x{y;}

--
Greetings from Bavaria, Germany

Helmut Weber, MVP WordVBA

Win XP, Office 2003
"red.sys" & Chr$(64) & "t-online.de"

You may find http://www.gmayor.com/replace_using_wildcards.htm useful?

--

Graham Mayor - Word MVP

My web site www.gmayor.com
Word MVP web site http://word.mvps.org


Steve Spicer wrote:
In Word2000 per the article;
http://support.microsoft.com/?kbid=212311
you can replace spaces with a tab specifying the minimum number of
times the space character must occur if I'm understanding this
correctly:


To convert multiple instances of white space characters, such as
spaces or tab characters, to a single instance of the character, use
the following advanced criteria in the Find What box in the Find and
Replace dialog box. x{y,}

where x is the character you are searching for, such as a space, and
y is the minimum number of instances that the character must appear
in order to be replaced.

Can you do this in Word 2003? and if so how?
Thanks, Steve

It's not a German page...I don't know why the link is taking your there.

"Helmut Weber" wrote:

Hmm...


http://support.microsoft.com/?kbid=212311


leads me to a page in German,

in case you are using a German, Dutch,
Norwegian?, Danish?, Swedish? ...? version,

the listseperator would be a semicolon ";",

US and most countries: x{y,}

some banana republics: x{y;}

--
Greetings from Bavaria, Germany

Helmut Weber, MVP WordVBA

Win XP, Office 2003
"red.sys" & Chr$(64) & "t-online.de"

Thanks Graham, I will have to study that. I don't know what's wrong with the
javascript on this newreader but the link you supply doesn't work when I
click on it here in the reader, but it's correct and I did find the page
going to your home.

"Graham Mayor" wrote:

You may find http://www.gmayor.com/replace_using_wildcards.htm useful?

--

Graham Mayor - Word MVP

My web site www.gmayor.com
Word MVP web site http://word.mvps.org


Steve Spicer wrote:
In Word2000 per the article;
http://support.microsoft.com/?kbid=212311
you can replace spaces with a tab specifying the minimum number of
times the space character must occur if I'm understanding this
correctly:


To convert multiple instances of white space characters, such as
spaces or tab characters, to a single instance of the character, use
the following advanced criteria in the Find What box in the Find and
Replace dialog box. x{y,}

where x is the character you are searching for, such as a space, and
y is the minimum number of instances that the character must appear
in order to be replaced.

Can you do this in Word 2003? and if so how?
Thanks, Steve

Yes, thanks... ^32{2,} in find worked using wildcards where 32 is the Ascii
for space. Finds at least 2 occurances of a space and replaces it with the
tab ^t. Thanks for your help.

"Graham Mayor" wrote:

You may find http://www.gmayor.com/replace_using_wildcards.htm useful?

--

Graham Mayor - Word MVP

My web site www.gmayor.com
Word MVP web site http://word.mvps.org


Steve Spicer wrote:
In Word2000 per the article;
http://support.microsoft.com/?kbid=212311
you can replace spaces with a tab specifying the minimum number of
times the space character must occur if I'm understanding this
correctly:


To convert multiple instances of white space characters, such as
spaces or tab characters, to a single instance of the character, use
the following advanced criteria in the Find What box in the Find and
Replace dialog box. x{y,}

where x is the character you are searching for, such as a space, and
y is the minimum number of instances that the character must appear
in order to be replaced.

Can you do this in Word 2003? and if so how?
Thanks, Steve