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How can I insert a section break within a column?
I have a rather complicated problem that I will try to carefully explain below.
I am writing an epic poem. (Yes, an epic poem.) The formatting I want is as follows: I want every page to have two columns. My poem has cantos (like chapters) and sections (within those cantos). The poem has 4 line stanzas, except that every section ends with a doublet (2-line stanza. I am using line numbering for every fourth line, so that the last line of every stanza has a line number by it. However, since the end of a section has a couplet instead of a quartet, a section messes this up so that the line number now shows in the middle of every stanza. I would rather have the line numbering COUNT the two lines of the couplet but not display the number till the end of the next quartet. Example: How it looks now: Blah blah blah Blah blah blah Blah blah blah 4 Blah blah blah Blah blah blah Blah blah blah **** Blah blah blah 8 Blah blah Blah Blah blah blah Blah blah Blah How I want it to look: How it looks now: Blah blah blah Blah blah blah Blah blah blah 4 Blah blah blah Blah blah blah Blah blah blah **** Blah blah blah Blah blah Blah Blah blah blah 10 Blah blah Blah I thought one way I could make this work would be to add a continuous section break. Then I could "reset" the line numbering with each section and begin the numbering of the second section manually so that it continues from the previous section. However, when I added the continuous section break, it split my columns. That is, it drew an invisible line horizontally across the page. The first section wrapped to the second column when it reached this line. The second section started on the left column below this line and wrapped to the second column below this line. I don't want the column formatting to behave any differently than if there were no section break. Example: # = lines * = section break What I want it to do: 1 10 2 3 11 4 12 13 5 14 6 15 * 16 17 7 18 8 9 What it does instead: 1 2 5 3 6 4 * 7 13 8 14 9 10 15 16 11 17 12 18 Is there any way to solve my problem? Thanks for reading through this long and complicated question. |
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