[Michael Koerner]

I do a mail merge from Excel into a Word table. Once the merge is completed, I have a macro (thanks to someone in this NG) which goes through the table, and when the first letter of the last name (column 1) changes it inserts a new row, combines all the cells sets the shading to 10%grey, centers an upper case character for that letter and inserts a border around that cell. The problem arises when the newly created cell is the first row on a new page, the last row on the previous page contains a bottom border which should not be there.

If I select the last row on the page, and delete the border, the border is removed from the top of the next page also. The only way I have found to keep the border where it is required and remove it from where it is not wanted is to delete the border one cell at a time rather than selecting the whole row at once. I was wondering if there might be an easier way to do this?

--

Regards
Michael Koerner

[Michael Koerner]

Forgot to add I'm using Office 2007 running under XP

--

Regards
Michael Koerner


"Michael Koerner" wrote in message ...
I do a mail merge from Excel into a Word table. Once the merge is completed, I have a macro (thanks to someone in this NG) which goes through the table, and when the first letter of the last name (column 1) changes it inserts a new row, combines all the cells sets the shading to 10%grey, centers an upper case character for that letter and inserts a border around that cell. The problem arises when the newly created cell is the first row on a new page, the last row on the previous page contains a bottom border which should not be there.

If I select the last row on the page, and delete the border, the border is removed from the top of the next page also. The only way I have found to keep the border where it is required and remove it from where it is not wanted is to delete the border one cell at a time rather than selecting the whole row at once. I was wondering if there might be an easier way to do this?

--

Regards
Michael Koerner

[Doug Robbins - Word MVP]

It might be better to modify the macro so that it splits the table before the row that is added so that the application of the border to that row will have no impact on the previous row.

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
I do a mail merge from Excel into a Word table. Once the merge is completed, I have a macro (thanks to someone in this NG) which goes through the table, and when the first letter of the last name (column 1) changes it inserts a new row, combines all the cells sets the shading to 10%grey, centers an upper case character for that letter and inserts a border around that cell. The problem arises when the newly created cell is the first row on a new page, the last row on the previous page contains a bottom border which should not be there.

If I select the last row on the page, and delete the border, the border is removed from the top of the next page also. The only way I have found to keep the border where it is required and remove it from where it is not wanted is to delete the border one cell at a time rather than selecting the whole row at once. I was wondering if there might be an easier way to do this?

--

Regards
Michael Koerner

[Michael Koerner]

Doug;

I thought of that. but my knowledge of macro programming is limited to the spelling of the word macro g Below is the code for the macro that someone provided for me awhile back. If you or anyone can change the code to do this, it would be greatly appreciated. Might be useful to others also.

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub



--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
It might be better to modify the macro so that it splits the table before the row that is added so that the application of the border to that row will have no impact on the previous row.

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
I do a mail merge from Excel into a Word table. Once the merge is completed, I have a macro (thanks to someone in this NG) which goes through the table, and when the first letter of the last name (column 1) changes it inserts a new row, combines all the cells sets the shading to 10%grey, centers an upper case character for that letter and inserts a border around that cell. The problem arises when the newly created cell is the first row on a new page, the last row on the previous page contains a bottom border which should not be there.

If I select the last row on the page, and delete the border, the border is removed from the top of the next page also. The only way I have found to keep the border where it is required and remove it from where it is not wanted is to delete the border one cell at a time rather than selecting the whole row at once. I was wondering if there might be an easier way to do this?

--

Regards
Michael Koerner

[Doug Robbins - Word MVP]

Try

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Doug;

I thought of that. but my knowledge of macro programming is limited to the spelling of the word macro g Below is the code for the macro that someone provided for me awhile back. If you or anyone can change the code to do this, it would be greatly appreciated. Might be useful to others also.

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub



--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
It might be better to modify the macro so that it splits the table before the row that is added so that the application of the border to that row will have no impact on the previous row.

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
I do a mail merge from Excel into a Word table. Once the merge is completed, I have a macro (thanks to someone in this NG) which goes through the table, and when the first letter of the last name (column 1) changes it inserts a new row, combines all the cells sets the shading to 10%grey, centers an upper case character for that letter and inserts a border around that cell. The problem arises when the newly created cell is the first row on a new page, the last row on the previous page contains a bottom border which should not be there.

If I select the last row on the page, and delete the border, the border is removed from the top of the next page also. The only way I have found to keep the border where it is required and remove it from where it is not wanted is to delete the border one cell at a time rather than selecting the whole row at once. I was wondering if there might be an easier way to do this?

--

Regards
Michael Koerner

[Michael Koerner]

Doug; thanks for taking the time. Greatly appreciated. The macro gives me a Run-time error '5': Invalid procedure call,and when I click on debug the following line is highlighted.

If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
Try

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Doug;

I thought of that. but my knowledge of macro programming is limited to the spelling of the word macro g Below is the code for the macro that someone provided for me awhile back. If you or anyone can change the code to do this, it would be greatly appreciated. Might be useful to others also.

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub



--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
It might be better to modify the macro so that it splits the table before the row that is added so that the application of the border to that row will have no impact on the previous row.

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
I do a mail merge from Excel into a Word table. Once the merge is completed, I have a macro (thanks to someone in this NG) which goes through the table, and when the first letter of the last name (column 1) changes it inserts a new row, combines all the cells sets the shading to 10%grey, centers an upper case character for that letter and inserts a border around that cell. The problem arises when the newly created cell is the first row on a new page, the last row on the previous page contains a bottom border which should not be there.

If I select the last row on the page, and delete the border, the border is removed from the top of the next page also. The only way I have found to keep the border where it is required and remove it from where it is not wanted is to delete the border one cell at a time rather than selecting the whole row at once. I was wondering if there might be an easier way to do this?

--

Regards
Michael Koerner

[Jay Freedman]

Michael Koerner wrote:
Doug; thanks for taking the time. Greatly appreciated. The macro
gives me a Run-time error '5': Invalid procedure call,and when I
click on debug the following line is highlighted.

If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow

Very interesting behavior...

When you call a method and you don't use its return value (that is, you use
it as a subroutine and not as a function), VBA prefers that you don't
enclose the argument in parentheses and in some cases considers it an error
(http://www.word.mvps.org/FAQs/Macros...thArgmnts.htm).

So changing the Split call to

dtable.Split BeforeRow:=newrow

or just

dtable.Split newrow

will work without errors.

According to the Help topic on the Split method, the argument can be either
a Row object (which newrow is) or the row number. That means you could write
the line as

dtable.Split BeforeRow:=newrow.Index

or just

dtable.Split newrow.Index

But now comes the odd part. You can write the line as

dtable.Split (newrow.Index)

and the macro will still work without errors, even though the parentheses
are "wrong". But this line gets a compiler error:

dtable.Split (BeforeRow:=newrow.Index)

--
Regards,
Jay Freedman
Microsoft Word MVP FAQ: http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.

[Michael Koerner]

Using this line

dtable.Split BeforeRow:=newrow

seems to work okay. Now how does one go about removing all thw whitespace between the tables?

--

Regards
Michael Koerner


"Jay Freedman" wrote in message ...
Michael Koerner wrote:
Doug; thanks for taking the time. Greatly appreciated. The macro
gives me a Run-time error '5': Invalid procedure call,and when I
click on debug the following line is highlighted.

If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow

Very interesting behavior...

When you call a method and you don't use its return value (that is, you use
it as a subroutine and not as a function), VBA prefers that you don't
enclose the argument in parentheses and in some cases considers it an error
(http://www.word.mvps.org/FAQs/Macros...thArgmnts.htm).

So changing the Split call to

dtable.Split BeforeRow:=newrow

or just

dtable.Split newrow

will work without errors.

According to the Help topic on the Split method, the argument can be either
a Row object (which newrow is) or the row number. That means you could write
the line as

dtable.Split BeforeRow:=newrow.Index

or just

dtable.Split newrow.Index

But now comes the odd part. You can write the line as

dtable.Split (newrow.Index)

and the macro will still work without errors, even though the parentheses
are "wrong". But this line gets a compiler error:

dtable.Split (BeforeRow:=newrow.Index)

--
Regards,
Jay Freedman
Microsoft Word MVP FAQ: http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.

[Doug Robbins - Word MVP]

I glad that fellow MVP stepped in to sort that out.

Re the white space, when you split a table, a paragraph mark is inserted between the two tables, so you will need to apply appropriate formatting to that paragraph mark - probably formatting the font as hidden

The following code splits a table at the row in which the selection is located and then formats the font of the paragraph between the two tables so that it is hidden:

Dim arow As Row
Dim arange As Range
Set arow = Selection.Rows(1)
Selection.Tables(1).Split arow
Set arange = arow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True


--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Using this line

dtable.Split BeforeRow:=newrow

seems to work okay. Now how does one go about removing all thw whitespace between the tables?

--

Regards
Michael Koerner


"Jay Freedman" wrote in message ...
Michael Koerner wrote:
Doug; thanks for taking the time. Greatly appreciated. The macro
gives me a Run-time error '5': Invalid procedure call,and when I
click on debug the following line is highlighted.

If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow

Very interesting behavior...

When you call a method and you don't use its return value (that is, you use
it as a subroutine and not as a function), VBA prefers that you don't
enclose the argument in parentheses and in some cases considers it an error
(http://www.word.mvps.org/FAQs/Macros...thArgmnts.htm).

So changing the Split call to

dtable.Split BeforeRow:=newrow

or just

dtable.Split newrow

will work without errors.

According to the Help topic on the Split method, the argument can be either
a Row object (which newrow is) or the row number. That means you could write
the line as

dtable.Split BeforeRow:=newrow.Index

or just

dtable.Split newrow.Index

But now comes the odd part. You can write the line as

dtable.Split (newrow.Index)

and the macro will still work without errors, even though the parentheses
are "wrong". But this line gets a compiler error:

dtable.Split (BeforeRow:=newrow.Index)

--
Regards,
Jay Freedman
Microsoft Word MVP FAQ: http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.

[Michael Koerner]

Thanks Doug. Where does one insert this in the original macro?

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
I glad that fellow MVP stepped in to sort that out.

Re the white space, when you split a table, a paragraph mark is inserted between the two tables, so you will need to apply appropriate formatting to that paragraph mark - probably formatting the font as hidden

The following code splits a table at the row in which the selection is located and then formats the font of the paragraph between the two tables so that it is hidden:

Dim arow As Row
Dim arange As Range
Set arow = Selection.Rows(1)
Selection.Tables(1).Split arow
Set arange = arow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True


--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Using this line

dtable.Split BeforeRow:=newrow

seems to work okay. Now how does one go about removing all thw whitespace between the tables?

--

Regards
Michael Koerner


"Jay Freedman" wrote in message ...
Michael Koerner wrote:
Doug; thanks for taking the time. Greatly appreciated. The macro
gives me a Run-time error '5': Invalid procedure call,and when I
click on debug the following line is highlighted.

If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow

Very interesting behavior...

When you call a method and you don't use its return value (that is, you use
it as a subroutine and not as a function), VBA prefers that you don't
enclose the argument in parentheses and in some cases considers it an error
(http://www.word.mvps.org/FAQs/Macros...thArgmnts.htm).

So changing the Split call to

dtable.Split BeforeRow:=newrow

or just

dtable.Split newrow

will work without errors.

According to the Help topic on the Split method, the argument can be either
a Row object (which newrow is) or the row number. That means you could write
the line as

dtable.Split BeforeRow:=newrow.Index

or just

dtable.Split newrow.Index

But now comes the odd part. You can write the line as

dtable.Split (newrow.Index)

and the macro will still work without errors, even though the parentheses
are "wrong". But this line gets a compiler error:

dtable.Split (BeforeRow:=newrow.Index)

--
Regards,
Jay Freedman
Microsoft Word MVP FAQ: http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.

[Doug Robbins - Word MVP]

Here is your original macro with all of the required modifications:

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range, arange As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
dtable.Split newrow
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
Set arange = newrow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub

Note that if you the paragraph marks ¶ being displayed in the document, the space between the tables will still appear, but if you click on the ¶ (Show/Hide) button to hide the paragraph marks, the space will disappear. In the ToolsOptionsPrint dialog, you must also have it set so that Hidden text is not printed.

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Thanks Doug. Where does one insert this in the original macro?

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
I glad that fellow MVP stepped in to sort that out.

Re the white space, when you split a table, a paragraph mark is inserted between the two tables, so you will need to apply appropriate formatting to that paragraph mark - probably formatting the font as hidden

The following code splits a table at the row in which the selection is located and then formats the font of the paragraph between the two tables so that it is hidden:

Dim arow As Row
Dim arange As Range
Set arow = Selection.Rows(1)
Selection.Tables(1).Split arow
Set arange = arow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True


--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Using this line

dtable.Split BeforeRow:=newrow

seems to work okay. Now how does one go about removing all thw whitespace between the tables?

--

Regards
Michael Koerner


"Jay Freedman" wrote in message ...
Michael Koerner wrote:
Doug; thanks for taking the time. Greatly appreciated. The macro
gives me a Run-time error '5': Invalid procedure call,and when I
click on debug the following line is highlighted.

If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow

Very interesting behavior...

When you call a method and you don't use its return value (that is, you use
it as a subroutine and not as a function), VBA prefers that you don't
enclose the argument in parentheses and in some cases considers it an error
(http://www.word.mvps.org/FAQs/Macros...thArgmnts.htm).

So changing the Split call to

dtable.Split BeforeRow:=newrow

or just

dtable.Split newrow

will work without errors.

According to the Help topic on the Split method, the argument can be either
a Row object (which newrow is) or the row number. That means you could write
the line as

dtable.Split BeforeRow:=newrow.Index

or just

dtable.Split newrow.Index

But now comes the odd part. You can write the line as

dtable.Split (newrow.Index)

and the macro will still work without errors, even though the parentheses
are "wrong". But this line gets a compiler error:

dtable.Split (BeforeRow:=newrow.Index)

--
Regards,
Jay Freedman
Microsoft Word MVP FAQ: http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.

[Michael Koerner]

Doug;

Thanks very much. Tried the macro a number of times, and each time I got the message the Word was recovering my document and if I wanted to send an error report to Microsoft.

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
Here is your original macro with all of the required modifications:

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range, arange As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
dtable.Split newrow
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
Set arange = newrow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub

Note that if you the paragraph marks ¶ being displayed in the document, the space between the tables will still appear, but if you click on the ¶ (Show/Hide) button to hide the paragraph marks, the space will disappear. In the ToolsOptionsPrint dialog, you must also have it set so that Hidden text is not printed.

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Thanks Doug. Where does one insert this in the original macro?

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
I glad that fellow MVP stepped in to sort that out.

Re the white space, when you split a table, a paragraph mark is inserted between the two tables, so you will need to apply appropriate formatting to that paragraph mark - probably formatting the font as hidden

The following code splits a table at the row in which the selection is located and then formats the font of the paragraph between the two tables so that it is hidden:

Dim arow As Row
Dim arange As Range
Set arow = Selection.Rows(1)
Selection.Tables(1).Split arow
Set arange = arow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True


--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Using this line

dtable.Split BeforeRow:=newrow

seems to work okay. Now how does one go about removing all thw whitespace between the tables?

--

Regards
Michael Koerner


"Jay Freedman" wrote in message ...
Michael Koerner wrote:
Doug; thanks for taking the time. Greatly appreciated. The macro
gives me a Run-time error '5': Invalid procedure call,and when I
click on debug the following line is highlighted.

If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow

Very interesting behavior...

When you call a method and you don't use its return value (that is, you use
it as a subroutine and not as a function), VBA prefers that you don't
enclose the argument in parentheses and in some cases considers it an error
(http://www.word.mvps.org/FAQs/Macros...thArgmnts.htm).

So changing the Split call to

dtable.Split BeforeRow:=newrow

or just

dtable.Split newrow

will work without errors.

According to the Help topic on the Split method, the argument can be either
a Row object (which newrow is) or the row number. That means you could write
the line as

dtable.Split BeforeRow:=newrow.Index

or just

dtable.Split newrow.Index

But now comes the odd part. You can write the line as

dtable.Split (newrow.Index)

and the macro will still work without errors, even though the parentheses
are "wrong". But this line gets a compiler error:

dtable.Split (BeforeRow:=newrow.Index)

--
Regards,
Jay Freedman
Microsoft Word MVP FAQ: http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.

[Doug Robbins - Word MVP]

Sorry, the Split command was in the wrong place. The following one should work:

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range, arange As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split newrow
Set arange = newrow.Range
arange.Start = arange.Start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub


--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Doug;

Thanks very much. Tried the macro a number of times, and each time I got the message the Word was recovering my document and if I wanted to send an error report to Microsoft.

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
Here is your original macro with all of the required modifications:

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range, arange As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
dtable.Split newrow
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
Set arange = newrow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub

Note that if you the paragraph marks ¶ being displayed in the document, the space between the tables will still appear, but if you click on the ¶ (Show/Hide) button to hide the paragraph marks, the space will disappear. In the ToolsOptionsPrint dialog, you must also have it set so that Hidden text is not printed.

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Thanks Doug. Where does one insert this in the original macro?

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
I glad that fellow MVP stepped in to sort that out.

Re the white space, when you split a table, a paragraph mark is inserted between the two tables, so you will need to apply appropriate formatting to that paragraph mark - probably formatting the font as hidden

The following code splits a table at the row in which the selection is located and then formats the font of the paragraph between the two tables so that it is hidden:

Dim arow As Row
Dim arange As Range
Set arow = Selection.Rows(1)
Selection.Tables(1).Split arow
Set arange = arow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True


--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Using this line

dtable.Split BeforeRow:=newrow

seems to work okay. Now how does one go about removing all thw whitespace between the tables?

--

Regards
Michael Koerner


"Jay Freedman" wrote in message ...
Michael Koerner wrote:
Doug; thanks for taking the time. Greatly appreciated. The macro
gives me a Run-time error '5': Invalid procedure call,and when I
click on debug the following line is highlighted.

If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow

Very interesting behavior...

When you call a method and you don't use its return value (that is, you use
it as a subroutine and not as a function), VBA prefers that you don't
enclose the argument in parentheses and in some cases considers it an error
(http://www.word.mvps.org/FAQs/Macros...thArgmnts.htm).

So changing the Split call to

dtable.Split BeforeRow:=newrow

or just

dtable.Split newrow

will work without errors.

According to the Help topic on the Split method, the argument can be either
a Row object (which newrow is) or the row number. That means you could write
the line as

dtable.Split BeforeRow:=newrow.Index

or just

dtable.Split newrow.Index

But now comes the odd part. You can write the line as

dtable.Split (newrow.Index)

and the macro will still work without errors, even though the parentheses
are "wrong". But this line gets a compiler error:

dtable.Split (BeforeRow:=newrow.Index)

--
Regards,
Jay Freedman
Microsoft Word MVP FAQ: http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.

[Michael Koerner]

Worked like a charm. thank you very much for all the time and effort. Greatly appreciated.

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
Sorry, the Split command was in the wrong place. The following one should work:

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range, arange As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split newrow
Set arange = newrow.Range
arange.Start = arange.Start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub


--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Doug;

Thanks very much. Tried the macro a number of times, and each time I got the message the Word was recovering my document and if I wanted to send an error report to Microsoft.

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
Here is your original macro with all of the required modifications:

Sub InsertFramedHeadRow()
' insert a framed header row into the table
Dim i As Long, j As Long
Dim Init As String
Dim newrow As Row
Dim initrng As Range, arange As Range
Dim dtable As Table
Set dtable = Selection.Tables(1)
j = dtable.Rows.Count
Init = dtable.Cell(j, 1).Range.Characters(1)
For i = j To 1 Step -1
Set initrng = dtable.Cell(i, 1).Range
If initrng.Characters(1) Init Then
dtable.Split newrow
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
Set arange = newrow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = "- " & Init & " -"
.Range.Font.Bold = True
.Range.Shading _
.BackgroundPatternColor = wdColorGray10
.Height = InchesToPoints(0.24)
.Borders.Enable = wdLineStyleSingle
.Borders.OutsideLineWidth = wdLineWidth100pt
End With
Init = initrng.Characters(1)
End If
Next i
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
With newrow
.Cells.Merge
.Cells(1).Range.ParagraphFormat.Alignment = wdAlignParagraphCenter
.Range.Text = Init
.Range.Font.Bold = True
.Range.Shading.BackgroundPatternColor = wdColorGray10
End With
End Sub

Note that if you the paragraph marks ¶ being displayed in the document, the space between the tables will still appear, but if you click on the ¶ (Show/Hide) button to hide the paragraph marks, the space will disappear. In the ToolsOptionsPrint dialog, you must also have it set so that Hidden text is not printed.

--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Thanks Doug. Where does one insert this in the original macro?

--

Regards
Michael Koerner


"Doug Robbins - Word MVP" wrote in message ...
I glad that fellow MVP stepped in to sort that out.

Re the white space, when you split a table, a paragraph mark is inserted between the two tables, so you will need to apply appropriate formatting to that paragraph mark - probably formatting the font as hidden

The following code splits a table at the row in which the selection is located and then formats the font of the paragraph between the two tables so that it is hidden:

Dim arow As Row
Dim arange As Range
Set arow = Selection.Rows(1)
Selection.Tables(1).Split arow
Set arange = arow.Range
arange.start = arange.start - 1
arange.Collapse wdCollapseStart
arange.Paragraphs(1).Range.Font.Hidden = True


--
Hope this helps.

Please reply to the newsgroup unless you wish to avail yourself of my
services on a paid consulting basis.

Doug Robbins - Word MVP

"Michael Koerner" wrote in message ...
Using this line

dtable.Split BeforeRow:=newrow

seems to work okay. Now how does one go about removing all thw whitespace between the tables?

--

Regards
Michael Koerner


"Jay Freedman" wrote in message ...
Michael Koerner wrote:
Doug; thanks for taking the time. Greatly appreciated. The macro
gives me a Run-time error '5': Invalid procedure call,and when I
click on debug the following line is highlighted.

If initrng.Characters(1) Init Then
Set newrow = dtable.Rows.Add(BeforeRow:=dtable.Rows(i + 1))
dtable.Split (newrow)
With newrow

Very interesting behavior...

When you call a method and you don't use its return value (that is, you use
it as a subroutine and not as a function), VBA prefers that you don't
enclose the argument in parentheses and in some cases considers it an error
(http://www.word.mvps.org/FAQs/Macros...thArgmnts.htm).

So changing the Split call to

dtable.Split BeforeRow:=newrow

or just

dtable.Split newrow

will work without errors.

According to the Help topic on the Split method, the argument can be either
a Row object (which newrow is) or the row number. That means you could write
the line as

dtable.Split BeforeRow:=newrow.Index

or just

dtable.Split newrow.Index

But now comes the odd part. You can write the line as

dtable.Split (newrow.Index)

and the macro will still work without errors, even though the parentheses
are "wrong". But this line gets a compiler error:

dtable.Split (BeforeRow:=newrow.Index)

--
Regards,
Jay Freedman
Microsoft Word MVP FAQ: http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.