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Count of a unique letter in a column
Many thanks, Graham, apologies for the confusion, the customer not knowing
what its right and left hands are doing! :-( The For i = 2 should work very well. I will have a play tomorrow when I have time. Jay, many thanks for the contribution as well. DeanH has left the building... ;-) "Graham Mayor" wrote: It is simple to fix if we know what you are dealing with. If you want to ignore the first table change the line For i = 1 To ActiveDocument.Tables.Count to For i = 2 To ActiveDocument.Tables.Count however the following version will skip any table with 1 or 2 columns If one or more of the tables have header rows then the following will also ignore any cell that contains anything other than Y or y or N or n Dim oTable As Table Dim lYesDOC As Long Dim lNoDOC As Long Dim lYesTAB As Long Dim lNoTAB As Long Dim oCell As Range lYesDOC = 0 lNoDOC = 0 For i = 1 To ActiveDocument.Tables.Count If ActiveDocument.Tables(i).Columns.Count 2 Then lYesTAB = 0 lNoTAB = 0 Set oTable = ActiveDocument.Tables(i) For j = 1 To oTable.Rows.Count Set oCell = oTable.Cell(j, 3).Range oCell.End = oCell.End - 1 If UCase(oCell.Text) = "Y" Then lYesDOC = lYesDOC + 1 lYesTAB = lYesTAB + 1 End If If UCase(oCell.Text) = "N" Then lNoDOC = lNoDOC + 1 lNoTAB = lNoTAB + 1 End If Next j If i = 1 Then ActiveDocument.Range.InsertAfter vbCr & _ "Sub totals:" End If ActiveDocument.Range.InsertAfter vbCr & _ "Table " & i & ": Yes - " & _ lYesTAB & " No - " & lNoTAB End If Next i ActiveDocument.Range.InsertAfter vbCr & _ "Totals: Yes - " & lYesDOC & " No - " & lNoDOC -- Graham Mayor - Word MVP My web site www.gmayor.com Word MVP web site http://word.mvps.org DeanH wrote: Hi Graham, just to test I deleted the superfluous table at the start. The macro works well, except it counts the "Y" and "N" in the header row. Doh! Simpe to fix? DeanH "Graham Mayor" wrote: The following macro will total the Ys and Ns for each table and add them with the total for the document at the end of the document. Dim oTable As Table Dim lYesDOC As Long Dim lNoDOC As Long Dim lYesTAB As Long Dim lNoTAB As Long Dim LastCell As Range lYesDOC = 0 lNoDOC = 0 For i = 1 To ActiveDocument.Tables.Count lYesTAB = 0 lNoTAB = 0 Set oTable = ActiveDocument.Tables(i) For j = 1 To oTable.Rows.Count If InStr(1, UCase(oTable.Cell(j, 3).Range), "Y") Then lYesDOC = lYesDOC + 1 lYesTAB = lYesTAB + 1 End If If InStr(1, UCase(oTable.Cell(j, 3).Range), "N") Then lNoDOC = lNoDOC + 1 lNoTAB = lNoTAB + 1 End If Next j If i = 1 Then ActiveDocument.Range.InsertAfter vbCr & _ "Sub totals:" End If ActiveDocument.Range.InsertAfter vbCr & _ "Table " & i & ": Yes - " & _ lYesTAB & " No - " & lNoTAB Next i ActiveDocument.Range.InsertAfter vbCr & _ "Totals: Yes - " & lYesDOC & " No - " & lNoDOC -- Graham Mayor - Word MVP My web site www.gmayor.com Word MVP web site http://word.mvps.org DeanH wrote: Word 2003 on XP. I have a document that contains multiple tables, in each table the thrid column contains "Y" or "N". I wish to count the occurances of both of these characters, either 1) at the bottom of each table, and/or 2) total number of both of these characters in all of the tables in the document. Any help will be greatly appreciated. DeanH |
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