Oops - missed the space, sorry.
I see that you have solved it yourself and posted how - thank you.
It can however be simpler by only wrapping parentheses around the elements
you want to refer to, so:
([a-z])[\!]( [a-z])
\1 is the first parenthesised expression - the lowercase letter before the !
\2 is the second parenthesised expression - the space and lowercase letter
after the !
You will not be able to refer to the ! in the replacement - but you don't
want to
--
Enjoy,
Tony
"Tony Jollans" My Forename at My Surname dot com wrote in message
...
Find: ([a-z])[\!]([a-z])
Replace: \1\2
--
Enjoy,
Tony
"A.N." wrote in message
...
I have the find code correctly as this: ([a-z][!][spacebar][a-z])
How to write the replace code without the !
Thanks.
"marrie" wrote in message
...
I would find the exclaim mark and then look at each one to see if
that's
what you want to remove. It is a bit tedious but that's what I can come
up
with for now.
--
This is a message from God: "Rebooting the universe, please log out"
"A.N." wrote in message
...
How do I find all ! in a document where there is a lowercase letter
on
its left and a space and lower case letter on its right and then
remove
it?
Example: end! another sentence
Thanks again.