[livetohike]

Is there any way to use something other than the 3 characters provided
as tab leader options?

I want to use my own character from the font I am using.

Alternatively, is there some way to accomplish the same thing?
Thanks

[Suzanne S. Barnhill]

At present Word doesn't offer any built-in way to use a different "fill"
character (WordPerfect does, I think).

--
Suzanne S. Barnhill
Microsoft MVP (Word)
Words into Type
Fairhope, Alabama USA
Word MVP FAQ site: http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.

"livetohike" wrote in message
ups.com...
Is there any way to use something other than the 3 characters provided
as tab leader options?

I want to use my own character from the font I am using.

Alternatively, is there some way to accomplish the same thing?
Thanks

[livetohike]

On Sep 4, 7:36 pm, "Suzanne S. Barnhill" wrote:
At present Word doesn't offer any built-in way to use a different "fill"
character (WordPerfect does, I think).

--
Suzanne S. Barnhill
Microsoft MVP (Word)
Words into Type
Fairhope, Alabama USA
Word MVP FAQ site:http://word.mvps.org
Email cannot be acknowledged; please post all follow-ups to the newsgroup so
all may benefit.

"livetohike" wrote in message

ups.com...

Is there any way to use something other than the 3 characters provided
as tab leader options?

I want to use my own character from the font I am using.

Alternatively, is there some way to accomplish the same thing?
Thanks

Thanks.
Any chance for a Macro or sophisticated substitution?

I tried to simply find/replace the default leader character (period)
w/ my character, but of course the periods are not really there and
Word must use special internal representation for the leader tab.

If a method could return the 'length' of a line of text using a
variable width font and then subtract that from the total length
available (left margin to the leader tab), you could then divide that
length by the width of my leader character to determine how many to
insert.

I am just thinking out of the box ;-)

I imagine VBA can tell me the number of characters in a line, but for
a non-fixed-width font, that won't help. I need it in pixels, or
points, inches or some other "real" unit.

Then it would need to iterate through each line of the selection and
do the actual replacement.
Possible?